Question

A circle has a center at `(7 ,6 )` and passes through `(2 ,1 )`. What is the length of an arc covering `pi` radians on the circle?

Answer 1

length of arc`=5pisqrt2`

Explanation:

compute the radius r first using the two points `(7, 6)` and `(2, 1)`

`r=sqrt((7-2)^2+(6-1)^2)=sqrt(5^2+5^2)=sqrt(2(25))=5sqrt2`

arc `s=r theta`

`s=(5sqrt2)*pi`

`s=5*pi*sqrt2`

God bless America !