A circle has a center at (7,6) and passes through (2,1). What is the length of an arc covering π8 radians on the circle?

1 Answer
Jan 27, 2016

52π8

Explanation:

We know the center and a point on the circle. The distance between the two points is the radius (draw a picture and convince yourself this).

We know that the distance between two points (x1,y1) and (x2,y2) on the Euclidean plane is given by d=(x1x2)2+(y1y2)2.
Thus, radius r=(72)2+(61)2=52+52=252=52.

By definition, a radian is the angle subtended by an arc of length equal to the radius. Thus, an arc which subtends an angle of θ has a length of θr. In this case, θ=π8, so arc length = 52π8.

Hint to remember
Note that the circumference subtends and angle of 2π at the center, and has a length of 2πr. By unitary method, an arc which subtends an angle of θ has a length of θr.