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How do you differentiate $f (x) = \frac{tan x}{cos x - 4}$ $f(x)=tanx/(cosx-4)$ ?

1 Answer

Feb 12, 2017

$f'(x)=(sec^2x(cosx-4)+sinxtanx)/(cosx-4)^2$

Explanation:

Using the quotient rule, we get:

$f'(x)=(sec^2x(cosx-4)+sinxtanx)/(cosx-4)^2$

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