How do you find the fourth roots of $16$ $16$ ?

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Answer 1 · 2017-02-09T10:00:58

$= \pm 2 and \pm i 2$ $=+-2 and +-i2$

Including complex roots, the fourth roots are

$\pm \sqrt{\pm \sqrt{16}}$ $+-sqrt(+-sqrt16)$

$= \pm \sqrt{4} and \pm \sqrt{(i^{2}) 4}$ $=+-sqrt4 and +-sqrt((i^2)4$

$= \pm 2 and \pm i 2$ $=+-2 and +-i2$ , where $i = \sqrt{- 1}$ $i=sqrt(-1)$ .

How do you find the fourth roots of 1616?