Question

How do you find the integral of `int (x^4-1)/(x^2+1)dx`?

Answer 1

We have that

#int (x^4-1)/(x^2+1)dx=int [(x^2+1)*(x^2-1)]/(x^2+1)dx= int (x^2-1)dx=x^3/3-x+c#