How do you find the integral of $sec^5 x dx$ ?

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Answer 1 · 2018-04-11T00:53:30

$1/6sec^6x$

first, to simplify, set $u=secx$ (or not)

now we have $intu^5dx$

to integrate, bring the power 5 up to 6 and add $1/6$ in front

so we have $1/6u^6$

so the answer is $1/6sec^6x$

How do you find the integral of sec^5 x dxsec^5 x dx?