How do you find the power #(2+3i)^-2# and express the result in rectangular form? Precalculus Complex Numbers in Trigonometric Form Powers of Complex Numbers 1 Answer Sonnhard Jul 8, 2018 #(13-6i)/169# Explanation: writing #(2-3i)^2/((2+3i)(2-3i))^2# this is #(4+9-6i)/(4+9)^2# #(13-6i)/(169)# Answer link Related questions How do I use DeMoivre's theorem to find #(1+i)^5#? How do I use DeMoivre's theorem to find #(1-i)^10#? How do I use DeMoivre's theorem to find #(2+2i)^6#? What is #i^2#? What is #i^3#? What is #i^4#? How do I find the value of a given power of #i#? How do I find the #n#th power of a complex number? How do I find the negative power of a complex number? Write the complex number #i^17# in standard form? See all questions in Powers of Complex Numbers Impact of this question 1466 views around the world You can reuse this answer Creative Commons License