How do you integrate int ((4-x)^2)^(3/2)dx((4x)2)32dx using trigonometric substitution?

1 Answer
May 1, 2018

The answer -[1/4*(4-x)^4]+c[14(4x)4]+c

Explanation:

Show the steps

int ((4-x)^2)^(3/2)dx=int(4-x)^(3/2*2)*dx=int(4-x)^3*dx((4x)2)32dx=(4x)322dx=(4x)3dx

-[1/4*(4-x)^4]+c[14(4x)4]+c

Note that

((x)^n)^m=x^(n*m)((x)n)m=xnm