How do you integrate $\int \frac{e^{x}}{\sqrt{- e^{2 x} - 36}} d x$ $int e^(x)/sqrt(-e^(2x) -36)dx$ using trigonometric substitution?

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Answer 1 · 2016-03-05T12:09:30

Is x real?
If so, $- e^{2 x} - 36$ $-e^(2x)-36$ < 0, for all x,.and $\sqrt{v a l u e < 0}$ $sqrt(value< 0)$ is imaginary..

How do you integrate int e^(x)/sqrt(-e^(2x) -36)dx∫ex√−e2x−36dxint e^(x)/sqrt(-e^(2x) -36)dx using trigonometric substitution?