How do you integrate $sin^2xcosx dx$ ?

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Answer 1 · 2015-02-04T17:00:12

I would use the fact that:

$d(sin(x))=cos(x)dx$ and substituting:

$intsin^2(x)*d(sin(x))=$

Now I use $sin(x)$ as my variable of integration and integrate it (as if it was a simple $x$ ).

$intsin^2(x)*d(sin(x))=sin^3(x)/3+c$

How do you integrate sin^2xcosx dxsin^2xcosx dx?