Question

How do you integrate `sin^2xcosx dx`?

Answer 1

I would use the fact that:

`d(sin(x))=cos(x)dx` and substituting:

`intsin^2(x)*d(sin(x))=`

Now I use `sin(x)` as my variable of integration and integrate it (as if it was a simple `x`).

`intsin^2(x)*d(sin(x))=sin^3(x)/3+c`