How do you simplify #(-i)^3#?

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Answer 1 · 2016-11-12T11:03:18

#i#

#(-i)^3# =#(-i)# x #(-i)# x #(-i)#

But #(-i)# x #(-i)# =#+i ^2# = -1

So #(-i)^3# =#(-i)# x #(-i)# x #(-i)#= #-i # x -1= #i #

Answer 2 · 2016-11-12T11:03:21

#i#

#i# is #sqrt(-1)#.

Therefore, #i^2# would be #-1#...

#-i^3=-i \times (-i) \times (-i)=-1 \times (-i) =i#