How do you simplify ${(- i)}^{3}$ $(-i)^3$ ?

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Answer 1 · 2016-11-12T11:03:18

$i$ $i$

${(- i)}^{3}$ $(-i)^3$ = $(- i)$ $(-i)$ x $(- i)$ $(-i)$ x $(- i)$ $(-i)$

But $(- i)$ $(-i)$ x $(- i)$ $(-i)$ = $+ i^{2}$ $+i ^2$ = -1

So ${(- i)}^{3}$ $(-i)^3$ = $(- i)$ $(-i)$ x $(- i)$ $(-i)$ x $(- i)$ $(-i)$ = $- i$ $-i$ x -1= $i$ $i$

Answer 2 · 2016-11-12T11:03:21

$i$ $i$

$i$ $i$ is $\sqrt{- 1}$ $sqrt(-1)$ .

Therefore, $i^{2}$ $i^2$ would be $- 1$ $-1$ ...

$- i^{3} = - i \times (- i) \times (- i) = - 1 \times (- i) = i$ $-i^3=-i \times (-i) \times (-i)=-1 \times (-i) =i$

How do you simplify (−i)3(-i)^3?