How do you simplify #i^76#? Precalculus Complex Numbers in Trigonometric Form Powers of Complex Numbers 1 Answer Shwetank Mauria May 7, 2016 #i^76=1# Explanation: #i^76=i^(4xx19)# As #a^(mxxn)=(a^m)^n# #i^76=i^(4xx19)=(i^4)^19# But #i^4=1# Hence #i^76=1^19=1# Answer link Related questions How do I use DeMoivre's theorem to find #(1+i)^5#? How do I use DeMoivre's theorem to find #(1-i)^10#? How do I use DeMoivre's theorem to find #(2+2i)^6#? What is #i^2#? What is #i^3#? What is #i^4#? How do I find the value of a given power of #i#? How do I find the #n#th power of a complex number? How do I find the negative power of a complex number? Write the complex number #i^17# in standard form? See all questions in Powers of Complex Numbers Impact of this question 3326 views around the world You can reuse this answer Creative Commons License