How do you simplify #sqrt(-2156)#?
2 Answers
Apr 4, 2018
Explanation:
Apr 4, 2018
Explanation:
The prime factorisation of
#2156 = 2^2 * 7^2 * 11#
Hence:
#sqrt(2156) = sqrt(14^2 * 11) = 14sqrt(11)#
and:
#sqrt(-2156) = sqrt(2156) i = 14sqrt(11)i#