Integrate the following x2+81dx?

1 Answer
Feb 7, 2017

xx2+812+812lnx+x2+819+C

Explanation:

Use trig substitution. Let x=9tanθ. Then dx=9sec2θdθ.

(9tanθ)2+819sec2θdθ

81tan2θ+819sec2θdθ

81(tan2θ+1)9sec2θdθ

81sec2θ9sec2θdθ

9secθ9sec2θdθ

81sec3θdθ

81sec3θdθ

This is a relatively known integral. The proof can be found here.

812secθtanθ+812ln|secθ+tanθ|+C

We know from our initial substitution that tanθ=x9. This means the hypotenuse of the triangle would have a hypotenuse of x2+81.

812(x2+819)(x9)+812lnx2+819+x9+C

xx2+812+812lnx+x2+819+C

Hopefully this helps!