What is #int (x)/(x+1)^3 dx#?
1 Answer
Mar 3, 2018
Explanation:
#int x/(x+1)^3 dx = int 1/(x+1)^2-1/(x+1)^3 dx#
#color(white)(int x/(x+1)^3 dx) = -1/(x+1)+1/(2(x+1)^2)+C#
#int x/(x+1)^3 dx = int 1/(x+1)^2-1/(x+1)^3 dx#
#color(white)(int x/(x+1)^3 dx) = -1/(x+1)+1/(2(x+1)^2)+C#