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What is the arclength of $r = - sin (- 5 θ^{2} + \frac{11 π}{8}) + 3 θ cos (7 θ - \frac{5 π}{8})$ $r=-sin(-5theta^2+(11pi)/8) +3thetacos(7theta -(5pi)/8)$ on $θ \in [\frac{7 π}{8}, \frac{13 π}{8}]$ $theta in [(7pi)/8,(13pi)/8]$ ?

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Feb 16, 2017

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