What is the arclength of the polar curve #f(theta) = 2tan^2theta+cos3theta # over #theta in [0,(5pi)/12] #?
1 Answer
Explanation:
The Arc Length L in polar is given by:
where
For this case we need evaluate
This a a nasty integral indeed:
Now add take the square root and compute using one of the online integral calculators.
I use Wolframalpha