Question

What is the slope of `r=tantheta^2-theta^2-theta` at `theta=(3pi)/8`?

Answer 1

`(dr)/(d theta) = 67.88`

Explanation:

`r=tantheta^2-theta^2-theta`

`(dr)/(d theta) = 2theta(sectheta^2)^2-2theta-1`

At `theta =(3pi)/8`

`(dr)/(d theta ) = 2times(3pi)/8times(sec((3pi)/8)^2)^2-2times(3pi)/8-1`

`(dr)/(d theta) = 67.88`