Consider a Cartesian coordinate system on a plane with origin O, axis OX (abscissa) and axis OY (ordinate).
A circle defined by equation x^2+y^2=16 has a radius R=sqrt(16)=4 and a center at origin O.
Point A=(4cos theta, 4sin theta) lies on this circle such that angle /_XOA=theta (counterclockwise from axis OX to radius OA)
Point B=(4cos(theta+60^o), 4sin(theta+60^o)) also lies on this circle making an angle between X-axis and radius OB larger than /_XOA by 60^o counterclockwise.
So, /_XOB=/_XOA+60^o
Therefore, the angle between radiuses OA and OB is /_AOB=60^o
Now it is obvious that triangle Delta AOB is equilateral since OA=OB as radiuses and /_AOB=60^o.
Therefore, AB=OA=OB=4.