Question #7c7e9

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Question #7c7e9

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Answer 1 · 2016-10-01T11:01:14

Length of the arc is $3.14 c m$ $3.14 cm$

Explanation:

Let $C D = 3 c m$ $CD=3 cm$ be the chord of the arc. $O$ $O$ be the centre of the circle, $O C = O D = r = 3 c m$ $OC=OD=r=3cm$ .

The triangle OCD is equilateral triangle.
So the angles of the triangle are of $60^{0}$ $60^0$ each.

The arc CD subtends $60^{0}$ $60^0$ angle at the centre.
Length of the arc is $l = 2 \cdot π \cdot r \cdot \frac{60}{360} = 2 \cdot \frac{22}{7} \cdot \frac{3}{6} = \frac{22}{7} = 3.14 c m$ $l=2*pi*r*60/360=2*22/7*3/6=22/7=3.14 cm$ [Ans]

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