A circle has a chord that goes from ( pi)/6 π6 to (5 pi) / 6 5π6 radians on the circle. If the area of the circle is 18 pi 18π, what is the length of the chord?

1 Answer
Apr 20, 2017

c = sqrt(54)c=54

Explanation:

We can compute the radius from the area of the circle:

pir^2=18piπr2=18π

r = sqrt18r=18

To radii and the chord form a triangle. The angle between the two radii is:

theta = (5pi)/6-pi/6= (2pi)/3θ=5π6π6=2π3

If we use the angle and the length of the two radii, we can use the Law of Cosines:

c^2=a^2+b^2-2(a)(b)cos(theta)c2=a2+b22(a)(b)cos(θ)

where a = b = r = sqrt18 and theta = (2pi)/3a=b=r=18andθ=2π3

c = sqrt((sqrt18)^2+(sqrt18)^2-2(sqrt18)(sqrt18)cos((2pi)/3)c=(18)2+(18)22(18)(18)cos(2π3)

c = sqrt(54)c=54