A circle's center is at $(2, 7)$ $(2 ,7 )$ and it passes through $(6, 4)$ $(6 ,4 )$ . What is the length of an arc covering $\frac{π}{3}$ $( pi ) /3$ radians on the circle?

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A circle's center is at $(2, 7)$ $(2 ,7 )$ and it passes through $(6, 4)$ $(6 ,4 )$ . What is the length of an arc covering $\frac{π}{3}$ $( pi ) /3$ radians on the circle?

1 Answer

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Answer 1 · 2016-01-29T05:45:52

$\frac{5 π}{3}$ $( 5 pi ) / 3$

Explanation:

Please check my solution here for a detailed explanation.

Solution
Radius $r = \sqrt{{(6 - 2)}^{2} + {(4 - 7)}^{2}} = 5$ $r = sqrt( (6 - 2)^2 + (4 - 7)^2 ) = 5$ .
Arc length $S = \frac{5 π}{3}$ $S = ( 5 pi ) / 3$ .

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A circle's center is at $(2, 7)$ $(2 ,7 )$ and it passes through $(6, 4)$ $(6 ,4 )$ . What is the length of an arc covering $\frac{π}{3}$ $( pi ) /3$ radians on the circle?

1 Answer

Explanation:

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A circle's center is at $(2, 7)$ $(2 ,7 )$ and it passes through $(6, 4)$ $(6 ,4 )$ . What is the length of an arc covering $\frac{π}{3}$ $( pi ) /3$ radians on the circle?