AB is diameter whose center is O of a circle. If AC is 3 cm and BC is 4 cm, then find AB?

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AB is diameter whose center is O of a circle. If AC is 3 cm and BC is 4 cm, then find AB?

1 Answer

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Answer 1 · 2017-02-27T01:23:21

$A B = 5$ $AB=5$

Explanation:

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I have to assume point $C$ $C$ is on the circle too.

In geometry, if $A, B and C$ $A,B and C$ are points on a circle when the line $A B$ $AB$ is a diameter of the circle, then $∠ A C B$ $angleACB$ is a right angle.

Given $A B$ $AB$ is a diameter, and $A C = 3, and B C = 4$ $AC=3, and BC=4$ ,
$\Rightarrow ∠ A C B = 90^{\circ}$ $=> angleACB=90^@$
by Pythagorean theorem,
$A B^{2} = A C^{2} + B C^{2}$ $AB^2=AC^2+BC^2$
$\Rightarrow A B^{2} = 3^{2} + 4^{2} = 25$ $=> AB^2=3^2+4^2=25$
$\Rightarrow A B = \sqrt{25} = 5$ $=> AB=sqrt25=5$

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AB is diameter whose center is O of a circle. If AC is 3 cm and BC is 4 cm, then find AB?

1 Answer

Explanation:

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